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4.9x^2-8.5x-20=0
a = 4.9; b = -8.5; c = -20;
Δ = b2-4ac
Δ = -8.52-4·4.9·(-20)
Δ = 464.25
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-8.5)-\sqrt{464.25}}{2*4.9}=\frac{8.5-\sqrt{464.25}}{9.8} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-8.5)+\sqrt{464.25}}{2*4.9}=\frac{8.5+\sqrt{464.25}}{9.8} $
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